Optimal. Leaf size=103 \[ \frac{2 a^2 (3 B+i A)}{3 c f (c-i c \tan (e+f x))^{3/2}}-\frac{4 a^2 (B+i A)}{5 f (c-i c \tan (e+f x))^{5/2}}-\frac{2 a^2 B}{c^2 f \sqrt{c-i c \tan (e+f x)}} \]
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Rubi [A] time = 0.179448, antiderivative size = 103, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.047, Rules used = {3588, 77} \[ \frac{2 a^2 (3 B+i A)}{3 c f (c-i c \tan (e+f x))^{3/2}}-\frac{4 a^2 (B+i A)}{5 f (c-i c \tan (e+f x))^{5/2}}-\frac{2 a^2 B}{c^2 f \sqrt{c-i c \tan (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 3588
Rule 77
Rubi steps
\begin{align*} \int \frac{(a+i a \tan (e+f x))^2 (A+B \tan (e+f x))}{(c-i c \tan (e+f x))^{5/2}} \, dx &=\frac{(a c) \operatorname{Subst}\left (\int \frac{(a+i a x) (A+B x)}{(c-i c x)^{7/2}} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{(a c) \operatorname{Subst}\left (\int \left (\frac{2 a (A-i B)}{(c-i c x)^{7/2}}-\frac{a (A-3 i B)}{c (c-i c x)^{5/2}}-\frac{i a B}{c^2 (c-i c x)^{3/2}}\right ) \, dx,x,\tan (e+f x)\right )}{f}\\ &=-\frac{4 a^2 (i A+B)}{5 f (c-i c \tan (e+f x))^{5/2}}+\frac{2 a^2 (i A+3 B)}{3 c f (c-i c \tan (e+f x))^{3/2}}-\frac{2 a^2 B}{c^2 f \sqrt{c-i c \tan (e+f x)}}\\ \end{align*}
Mathematica [A] time = 11.9614, size = 118, normalized size = 1.15 \[ \frac{a^2 \cos (e+f x) \sqrt{c-i c \tan (e+f x)} (\cos (3 e+5 f x)+i \sin (3 e+5 f x)) (5 (A+3 i B) \sin (2 (e+f x))+(-21 B-i A) \cos (2 (e+f x))-i A+9 B)}{15 c^3 f (\cos (f x)+i \sin (f x))^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.081, size = 80, normalized size = 0.8 \begin{align*}{\frac{-2\,i{a}^{2}}{f{c}^{2}} \left ({-iB{\frac{1}{\sqrt{c-ic\tan \left ( fx+e \right ) }}}}-{\frac{c \left ( A-3\,iB \right ) }{3} \left ( c-ic\tan \left ( fx+e \right ) \right ) ^{-{\frac{3}{2}}}}+{\frac{2\,{c}^{2} \left ( A-iB \right ) }{5} \left ( c-ic\tan \left ( fx+e \right ) \right ) ^{-{\frac{5}{2}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.15955, size = 107, normalized size = 1.04 \begin{align*} \frac{2 i \,{\left (15 i \,{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{2} B a^{2} +{\left (-i \, c \tan \left (f x + e\right ) + c\right )}{\left (5 \, A - 15 i \, B\right )} a^{2} c -{\left (6 \, A - 6 i \, B\right )} a^{2} c^{2}\right )}}{15 \,{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac{5}{2}} c^{2} f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.18839, size = 266, normalized size = 2.58 \begin{align*} \frac{\sqrt{2}{\left ({\left (-3 i \, A - 3 \, B\right )} a^{2} e^{\left (6 i \, f x + 6 i \, e\right )} +{\left (-4 i \, A + 6 \, B\right )} a^{2} e^{\left (4 i \, f x + 4 i \, e\right )} +{\left (i \, A - 9 \, B\right )} a^{2} e^{\left (2 i \, f x + 2 i \, e\right )} +{\left (2 i \, A - 18 \, B\right )} a^{2}\right )} \sqrt{\frac{c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}}{30 \, c^{3} f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \tan \left (f x + e\right ) + A\right )}{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{2}}{{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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